xat previous year question paper with solution

  • Delta Key Actual Question in XAT 2023

    Q. Suppose Haruka has a special key Δ in her calculator called delta key: Rule 1: If the display shows a one-digit number, pressing delta key Δ replaces the displayed number with twice its value.Rule 2: If the display shows a two-digit number, pressing delta key Δ replaces the displayed number with the sum of the two digits. Suppose Haruka enters…

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  • Ratio Actual Question in XAT 2023

    Q. A small jar contained water, lime and sugar in the ratio of 90:7:3. A glass contained only water and sugar in it. Contents of both (small jar and glass) were mixed in a bigger jar and the ratio of contents in the bigger jar was 85:5:10 (water, lime and sugar respectively). Find the percentage of…

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  • Number System Actual Questions in XAT 2023

    Q1. The addition of 7 distinct positive integers is 1740. What is the largest possible “greatest common divisor” of these 7 distinct positive integers? Q2. Five students appeared for an examination. The average mark obtained by these five students is 40. The maximum mark of the examination is 100, and each of the five students scored…

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  • Area Actual Question in XAT 2023

    Q. ABCD is a trapezoid where BC is parallel to AD and perpendicular to AB . Kindly note that BC<AD . P is a point on AD such that CPD is an equilateral triangle. Q is a point on BC such that AQ is parallel to PC . If the area of the triangle CPD…

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  • A.P Actual Questions in XAT 2023

    Q1. Q2. Separately, Jack and Sristi invested the same amount of money in a stock market. Jack’s invested amount kept getting reduced by 50% every month. Sristi’s investment also reduced every month, but in an arithmetic progression with a common difference of Rs. 15000. They both withdrew their respective amounts at the end of the…

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  • Integers Actual Questions in XAT 2023

    Q1. Raju and Sarita play a number game. First, each one of them chooses a positive integer independently. Separately, they both multiply their chosen integers by 2, and then subtract 20 from their resultant numbers. Now, each of them has a new number. Then, they divide their respective new numbers by 5. Finally, they added…

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