**Q1. Raju and Sarita play a number game. First, each one of them chooses a positive integer independently. Separately, they both multiply their chosen integers by 2, and then subtract 20 from their resultant numbers. Now, each of them has a new number. Then, they divide their respective new numbers by 5. Finally, they added their results and found that the sum is 16.** **What can be the maximum possible difference between the positive integers chosen by Raju and Sarita?**

- 67
- 58
- 49
- 40
- None of the above

## EXPLANATION

r and s are positive integers. For their difference to be as large as possible. r and s should be as far apart as possible.

r = 1; s = 59

The max difference between r and s is 59 – 1 = 58.

**Q2. Let x and y be two positive integers and p be a prime number. If x (x – p) – y (y + p) = 7p,** **what will be the minimum value of x – y?**

- 1
- 3
- 5
- 7
- None of the above

## EXPLANATION

For x and y to be integers, s and d should both be even or should both be odd.

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